WolframAlpha Computational Intelligence Natural Language Math Input NEW Use textbook math notation to enter your math Try it × Extended Keyboard Examples Compute expertlevel answers using Wolfram's breakthrough algorithms, knowledgebase and AI technologyExtended Keyboard Examples Upload Random Compute answers using Wolfram's breakthrough technology & knowledgebase, relied on by millions of students & professionals For math, science, nutrition, history, geography, engineering, mathematics, linguistics, sports, finance, music WolframAlpha brings expertlevel knowledge See the explanantion This is the equation of a circle with its centre at the origin Think of the axis as the sides of a triangle with the Hypotenuse being the line from the centre to the point on the circle By using Pythagoras you would end up with the equation given where the 4 is in fact r^2 To obtain the plot points manipulate the equation as below Given" "x^2y^2=r^2" ">"

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X^2+y^2+z^2=4 graph
X^2+y^2+z^2=4 graph-This tool graphs z = f (x,y) mathematical functions in 3D It is more of a tour than a tool All functions can be set different boundaries for x, y, and z, to maximize your viewing enjoyment This tool looks really great with a very high detail level, but you may find it more comfortable to use less detail if you want to spin the modelSketch the graph of 4x^2y^2=4 algebraically finding and labeling the vertices, foci and asymptotes




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Showing how to graph a simple quadratic with 5 pointsAll equations of the form a x 2 b x c = 0 can be solved using the quadratic formula 2 a − b ± b 2 − 4 a c The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction x^ {2}2xy^ {2}2yz^ {2}1=0 x 2 − 2 x y 2 − 2 y z 2 1 = 0 Graph graph{2(x2)^24 654, 1346, 122, 22} See explanation below There are more rigorous ways to draw the graph of an parabola by hand (using calculus, mostly), but for our purposes, here's what we're going to do Step 1 Identify the Vertex This is just because you have your parabola in vertex form, which makes this process very easy For a parabola in vertex
Math2org Math Tables Algebraic Graphs Conic Sections (see also Conic Sections) Point x ^2 y ^2 = 0 Circle x ^2 y ^2 = r ^2 Ellipse x ^2 / a ^2 y ^2 / b ^2 = 1 Ellipse x ^2 / b ^2 y ^2 / a ^2 = 1 Hyperbola x ^2 / a ^2 y ^2 / b ^2 = 1 Parabola 4px = y ^2 Parabola 4py = x ^2 Hyperbola y ^2 / a ^2 x ^2 / b ^2 = 1 For any of the above with a center at (j, k) instead of (0,0Seriously I tried for like 15 minutes and created new graphs a few times but this time it just worked It was saying "Please enter an explicit function in x" Now it's just mocking me with perfect graphs every time lol Second question This is far more frustrating on android Sometimes it's my fault like if I reuse a variable by mistake which maybe cascades I just wish there were a way to One may recognize an ellipsoid, a particular quadric surface If one chooses a cartesian coordinate system, such that the origin is the center of the ellipsoid, and the coordinate axes are axes of the ellipsoid, the implicit equation of the ellipsoid has the standard form x 2 a 2 y 2 b 2 z 2 c 2 = 1 The line segments from the origin to
Graph x=y^24 Find the properties of the given parabola Tap for more steps Rewrite the equation in vertex form Tap for more steps Complete the square for Tap for more steps Use the form , to find the values of , , and Consider the vertex form of a parabola Substitute the values of and into the formula Cancel the common factor of and Tap for more steps Factor out of Plot z = x^2 y^2 over the interval 4The square root keeps us from going above that point z=4 if we manipulate the equation and isolate x 2 y 2 we get x 2 y 2 = 16 z 2 (remember that since we have a square root in our original function, we have to consider it's domain in our graph, meaning z



Solution Write The Parabola In Standard Form And Graph X 2 4y 28 0 Write The Ellipse In Standard Form And Graph 2x 2 Y 2 4x 4y 4 0 Write The Hyperbola In Standard Form And Graph X 2




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To raise a power to another power, multiply the exponents Multiply 2 and 4 to get 8 2x^ {2}y^ {3}z^ {3}\left (3\right)^ {4}x^ {4}y^ {8}z^ {4} − 2 x 2 y 3 z 3 ( − 3) 4 x 4 y 8 z 4 Calculate 3 to the power of 4 and get 81 Calculate − 3 to the power of 4 and get 8 1Get stepbystep solutions from expert tutors as fast as 1530 minutes Your first 5 questions are on us! How to plot 3 dimensional graph for x^2 y^2 = 1?



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For example, if we want to plot the top half of the sphere with equation x^2 y^2 z^2 = 16, we solve for z and obtain z = sqrt (16 x^2 y^2) or z = sqrt (16 r^2) Now we draw the graph parametrically, as follows > cylinderplot(r,theta,sqrt(16r^2),r=04,theta=02*Pi);I am already using it and I only can plot in 2 dimensional graph Can someone help me with this problem?Cos(x^2) (x−3)(x3) Zooming and Recentering To zoom, use the zoom slider To the left zooms in, to the right zooms out When you let go of the slider it goes back to the middle so you can zoom more You can clickanddrag to move the graph around If you just clickandrelease (without moving), then the spot you clicked on




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Surface Area
If you don't include an equals sign, it will assume you mean "=0" It has not been well tested, so have fun with it, but don't trust it If it gives you problems, let me know Note it may take a few seconds to finish, because it has to do lots of calculations If you justUse "x" as the variable like this Examples sin(x) 2x−3;Next, let us draw the cylinder x^2 y^2 = 2 In this cylinder, the radius r is always 2 We let theta vary from 0




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The axis of symmetry is the line y = 1 And if we start at the vertex (1,1) and go ±1 in the y direction (vertically), the we'll go a = −1 in the x direction (horizontally) This gives us 2 additional points (0,0) and (0,2) That's enough to sketch the graph graph {x=2yy^2 4933, 4932, 2466, 2467} Answer linkExtended Keyboard Examples Upload Random Compute answers using Wolfram's breakthrough technology & knowledgebase, relied on by millions of students & professionals For math, science, nutrition, history, geography, engineering, mathematics, linguistics, sports, finance, music WolframAlpha brings expertlevel knowledgeAnswer (1 of 11) x^2y^22x=0 Complete the square x^22xy^2=0 x^22x11y^2=0 (x^22x1)y^2=1 (x1)^2y^2=1 This is a circle with its center at (1,0) and a




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